CUBRID Q&A http://www.cubrid.org/?mid=questions CUBRID Q&A en Fri, 21 Oct 2011 02:37:10 -0800 Wed, 20 Mar 2013 22:07:09 -0800 XpressEngine 1.4.4.1 Can't create composite foreign key with a different cardinality ovidiuv http://www.cubrid.org/questions/435664 http://www.cubrid.org/questions/435664 I can't create composite foreign key with a different cardinality than the referenced table's primary key, even if there is a unique index:

CREATE TABLE "ITEMS" (
  "ID" integer AUTO_INCREMENT PRIMARY KEY,
  "ITEM_ID" integer FOREIGN KEY REFERENCES "ITEMS",
  UNIQUE ("ITEM_ID", "ID"),
  FOREIGN KEY ("ID", "ITEM_ID") REFERENCES "ITEMS"("ITEM_ID", "ID")
);

gives error:

The number of keys of the foreign key 'fk_items_id_item_id' is different from that of the primary key 'pk_items_id'.

]]> Tue, 25 Sep 2012 02:00:42 -0800 foreign key cardinality unique primary key 1 How to navigate foreign key relationships using the dictionary views? lukaseder http://www.cubrid.org/questions/317560 http://www.cubrid.org/questions/317560 I am implementing a CUBRID integration for jOOQ, and I wonder how I can discover foreign key relationships using the dictionary views. Using the following query, I can discover foreign key columns:

select k.class_name, k.index_name, k.key_attr_name
from db_index  i
join db_index_key k
on i.index_name = k.index_name
and i.class_name = k.class_name
where is_foreign_key = 'YES'
order by k.class_name, k.index_name, k.key_order

Now, how can I discover which columns (or which primary key) is referenced?

]]> Thu, 29 Mar 2012 08:54:05 -0800 SQL index foreign key 2